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12022320153 = 34007440051
BaseRepresentation
bin10110011001001011…
…00000110000011001
31011000212010010211210
423030211200300121
5144110203221103
65304544013333
7603632015034
oct131445406031
934025103753
1012022320153
11510a317088
1223b6301249
13119797b00c
1482098c01b
154a56cde03
hex2cc960c19

12022320153 has 4 divisors (see below), whose sum is σ = 16029760208. Its totient is φ = 8014880100.

The previous prime is 12022320119. The next prime is 12022320157. The reversal of 12022320153 is 35102322021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12022320153 - 210 = 12022319129 is a prime.

It is a super-2 number, since 2×120223201532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12022320157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003720023 + ... + 2003720028.

It is an arithmetic number, because the mean of its divisors is an integer number (4007440052).

Almost surely, 212022320153 is an apocalyptic number.

It is an amenable number.

12022320153 is a deficient number, since it is larger than the sum of its proper divisors (4007440055).

12022320153 is an equidigital number, since it uses as much as digits as its factorization.

12022320153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4007440054.

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 12022320153 its reverse (35102322021), we get a palindrome (47124642174).

The spelling of 12022320153 in words is "twelve billion, twenty-two million, three hundred twenty thousand, one hundred fifty-three".

Divisors: 1 3 4007440051 12022320153