12023101300433 has 8 divisors (see below), whose sum is σ = 12053978905920. Its totient is φ = 11992234090320.

The previous prime is 12023101300429. The next prime is 12023101300451. The reversal of 12023101300433 is 33400310132021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12023101300433 - 2² = 12023101300429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12023101300399 and 12023101300408.

It is not an unprimeable number, because it can be changed into a prime (12023101305433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 280058 + ... + 4911683.

It is an arithmetic number, because the mean of its divisors is an integer number (1506747363240).

Almost surely, 2^{12023101300433} is an apocalyptic number.

It is an amenable number.

12023101300433 is a deficient number, since it is larger than the sum of its proper divisors (30877605487).

12023101300433 is an equidigital number, since it uses as much as digits as its factorization.

12023101300433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5197687.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 12023101300433 its reverse (33400310132021), we get a palindrome (45423411432454).

The spelling of 12023101300433 in words is "twelve trillion, twenty-three billion, one hundred one million, three hundred thousand, four hundred thirty-three".