120231301111121 has 4 divisors (see below), whose sum is σ = 120231395426544. Its totient is φ = 120231206795700.

The previous prime is 120231301111079. The next prime is 120231301111151. The reversal of 120231301111121 is 121111103132021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120231301111121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120231301111093 and 120231301111102.

It is not an unprimeable number, because it can be changed into a prime (120231301111151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45218975 + ... + 47803956.

It is an arithmetic number, because the mean of its divisors is an integer number (30057848856636).

Almost surely, 2^{120231301111121} is an apocalyptic number.

It is an amenable number.

120231301111121 is a deficient number, since it is larger than the sum of its proper divisors (94315423).

120231301111121 is an equidigital number, since it uses as much as digits as its factorization.

120231301111121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94315422.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 120231301111121 its reverse (121111103132021), we get a palindrome (241342404243142).

The spelling of 120231301111121 in words is "one hundred twenty trillion, two hundred thirty-one billion, three hundred one million, one hundred eleven thousand, one hundred twenty-one".