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1202331014131 = 13266047107717
BaseRepresentation
bin10001011111110000100…
…000110101001111110011
311020221102111220220020011
4101133300200311033303
5124144333214423011
62320202050155351
7152602611665422
oct21376040651763
94227374826204
101202331014131
114239a6570555
1217502a282b57
13894c14cb600
144229bd4b2b9
152141e686621
hex117f08353f3

1202331014131 has 12 divisors (see below), whose sum is σ = 1301964198912. Its totient is φ = 1109816906016.

The previous prime is 1202331014069. The next prime is 1202331014161. The reversal of 1202331014131 is 1314101332021.

It is not a de Polignac number, because 1202331014131 - 217 = 1202330883059 is a prime.

It is a super-2 number, since 2×12023310141312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1202331014161) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11108085 + ... + 11215801.

It is an arithmetic number, because the mean of its divisors is an integer number (108497016576).

Almost surely, 21202331014131 is an apocalyptic number.

1202331014131 is a deficient number, since it is larger than the sum of its proper divisors (99633184781).

1202331014131 is a wasteful number, since it uses less digits than its factorization.

1202331014131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 173790 (or 173777 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1202331014131 its reverse (1314101332021), we get a palindrome (2516432346152).

The spelling of 1202331014131 in words is "one trillion, two hundred two billion, three hundred thirty-one million, fourteen thousand, one hundred thirty-one".

Divisors: 1 13 169 66047 107717 858611 1400321 11161943 18204173 7114384699 92487001087 1202331014131