Base | Representation |
---|---|
bin | 11011010101101000111100… |
… | …001000110111000111110001 |
3 | 120202201021210201200010200120 |
4 | 123111220330020313013301 |
5 | 111224404343300040423 |
6 | 1103414515145240453 |
7 | 34216433422440531 |
oct | 3325507410670761 |
9 | 522637721603616 |
10 | 120234323440113 |
11 | 353460aa096a43 |
12 | 1159a273793129 |
13 | 521208174960c |
14 | 219952d8654c1 |
15 | dd7886067ee3 |
hex | 6d5a3c2371f1 |
120234323440113 has 8 divisors (see below), whose sum is σ = 160312532472288. Its totient is φ = 80156165017344.
The previous prime is 120234323440039. The next prime is 120234323440129. The reversal of 120234323440113 is 311044323432021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-120234323440113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (120234323440313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6710320 + ... + 16896657.
It is an arithmetic number, because the mean of its divisors is an integer number (20039066559036).
Almost surely, 2120234323440113 is an apocalyptic number.
It is an amenable number.
120234323440113 is a deficient number, since it is larger than the sum of its proper divisors (40078209032175).
120234323440113 is a wasteful number, since it uses less digits than its factorization.
120234323440113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25304703.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 120234323440113 its reverse (311044323432021), we get a palindrome (431278646872134).
The spelling of 120234323440113 in words is "one hundred twenty trillion, two hundred thirty-four billion, three hundred twenty-three million, four hundred forty thousand, one hundred thirteen".
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