Base | Representation |
---|---|
bin | 10110011001011001… |
… | …01111001110100001 |
3 | 1011000222200101022022 |
4 | 23030230233032201 |
5 | 144111144330213 |
6 | 5305052351225 |
7 | 603654064520 |
oct | 131454571641 |
9 | 34028611268 |
10 | 12024214433 |
11 | 51103a0300 |
12 | 23b6a75515 |
13 | 11981922aa |
14 | 820d224b7 |
15 | 4a5955308 |
hex | 2ccb2f3a1 |
12024214433 has 12 divisors (see below), whose sum is σ = 15104799360. Its totient is φ = 9369517080.
The previous prime is 12024214339. The next prime is 12024214439. The reversal of 12024214433 is 33441242021.
It is not a de Polignac number, because 12024214433 - 212 = 12024210337 is a prime.
It is a super-2 number, since 2×120242144332 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12024214439) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7097273 + ... + 7098966.
It is an arithmetic number, because the mean of its divisors is an integer number (1258733280).
Almost surely, 212024214433 is an apocalyptic number.
It is an amenable number.
12024214433 is a deficient number, since it is larger than the sum of its proper divisors (3080584927).
12024214433 is a wasteful number, since it uses less digits than its factorization.
12024214433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14196268 (or 14196257 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 12024214433 its reverse (33441242021), we get a palindrome (45465456454).
The spelling of 12024214433 in words is "twelve billion, twenty-four million, two hundred fourteen thousand, four hundred thirty-three".
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