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1202500113 = 3400833371
BaseRepresentation
bin100011110101100…
…1011001000010001
310002210201100001020
41013223023020101
54430320000423
6315153430053
741541040143
oct10753131021
93083640036
101202500113
11567864151
1229686b329
1316218b439
14b59c0c93
15708814e3
hex47acb211

1202500113 has 4 divisors (see below), whose sum is σ = 1603333488. Its totient is φ = 801666740.

The previous prime is 1202500043. The next prime is 1202500129. The reversal of 1202500113 is 3110052021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1202500113 - 216 = 1202434577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1202500092 and 1202500101.

It is not an unprimeable number, because it can be changed into a prime (1202500163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200416683 + ... + 200416688.

It is an arithmetic number, because the mean of its divisors is an integer number (400833372).

Almost surely, 21202500113 is an apocalyptic number.

It is an amenable number.

1202500113 is a deficient number, since it is larger than the sum of its proper divisors (400833375).

1202500113 is an equidigital number, since it uses as much as digits as its factorization.

1202500113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400833374.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 1202500113 is about 34677.0833981176. The cubic root of 1202500113 is about 1063.3960479537.

Adding to 1202500113 its reverse (3110052021), we get a palindrome (4312552134).

The spelling of 1202500113 in words is "one billion, two hundred two million, five hundred thousand, one hundred thirteen".

Divisors: 1 3 400833371 1202500113