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12025425417 = 34008475139
BaseRepresentation
bin10110011001100010…
…10110111000001001
31011001001221220110120
423030301112320021
5144112002103132
65305134333453
7604000300215
oct131461267011
934031856416
1012025425417
115111048115
1223b735a289
1311984c7555
14821159945
154a5ae402c
hex2ccc56e09

12025425417 has 4 divisors (see below), whose sum is σ = 16033900560. Its totient is φ = 8016950276.

The previous prime is 12025425361. The next prime is 12025425421. The reversal of 12025425417 is 71452452021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12025425417 - 212 = 12025421321 is a prime.

It is a super-2 number, since 2×120254254172 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12025425437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2004237567 + ... + 2004237572.

It is an arithmetic number, because the mean of its divisors is an integer number (4008475140).

Almost surely, 212025425417 is an apocalyptic number.

It is an amenable number.

12025425417 is a deficient number, since it is larger than the sum of its proper divisors (4008475143).

12025425417 is an equidigital number, since it uses as much as digits as its factorization.

12025425417 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4008475142.

The product of its (nonzero) digits is 22400, while the sum is 33.

Adding to 12025425417 its reverse (71452452021), we get a palindrome (83477877438).

The spelling of 12025425417 in words is "twelve billion, twenty-five million, four hundred twenty-five thousand, four hundred seventeen".

Divisors: 1 3 4008475139 12025425417