Base | Representation |
---|---|
bin | 11011010110100111001110… |
… | …111101110110001111101011 |
3 | 120202221200110021000010220212 |
4 | 123112213032331312033223 |
5 | 111232003340044010011 |
6 | 1103505340304411335 |
7 | 34224322110123632 |
oct | 3326471675661753 |
9 | 522850407003825 |
10 | 120301211313131 |
11 | 353715035a3a42 |
12 | 115ab220316b4b |
13 | 52184811b11c4 |
14 | 219c877008519 |
15 | dd949d33708b |
hex | 6d69cef763eb |
120301211313131 has 8 divisors (see below), whose sum is σ = 125844745401504. Its totient is φ = 114783764444800.
The previous prime is 120301211313121. The next prime is 120301211313137. The reversal of 120301211313131 is 131313112103021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 120301211313131 - 242 = 115903164802027 is a prime.
It is a super-2 number, since 2×1203012113131312 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120301211313097 and 120301211313106.
It is not an unprimeable number, because it can be changed into a prime (120301211313137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6521795576 + ... + 6521814021.
It is an arithmetic number, because the mean of its divisors is an integer number (15730593175188).
Almost surely, 2120301211313131 is an apocalyptic number.
120301211313131 is a deficient number, since it is larger than the sum of its proper divisors (5543534088373).
120301211313131 is a wasteful number, since it uses less digits than its factorization.
120301211313131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13043610021.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 120301211313131 its reverse (131313112103021), we get a palindrome (251614323416152).
The spelling of 120301211313131 in words is "one hundred twenty trillion, three hundred one billion, two hundred eleven million, three hundred thirteen thousand, one hundred thirty-one".
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