1203040113 has 16 divisors (see below), whose sum is σ = 1750526400. Its totient is φ = 728844480.

The previous prime is 1203040099. The next prime is 1203040121. The reversal of 1203040113 is 3110403021.

It is not a de Polignac number, because 1203040113 - 2¹⁴ = 1203023729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1203040092 and 1203040101.

It is not an unprimeable number, because it can be changed into a prime (1203040183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117483 + ... + 127311.

It is an arithmetic number, because the mean of its divisors is an integer number (109407900).

Almost surely, 2^1203040113 is an apocalyptic number.

It is an amenable number.

1203040113 is a deficient number, since it is larger than the sum of its proper divisors (547486287).

1203040113 is a wasteful number, since it uses less digits than its factorization.

1203040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13552.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 1203040113 is about 34684.8686461402. The cubic root of 1203040113 is about 1063.5552019044. Note that the first 3 decimals are identical.

Adding to 1203040113 its reverse (3110403021), we get a palindrome (4313443134).

The spelling of 1203040113 in words is "one billion, two hundred three million, forty thousand, one hundred thirteen".