120330100115 has 4 divisors (see below), whose sum is σ = 144396120144. Its totient is φ = 96264080088.

The previous prime is 120330100087. The next prime is 120330100129. The reversal of 120330100115 is 511001033021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511001033021 = 31 ⋅16483904291.

It is a cyclic number.

It is not a de Polignac number, because 120330100115 - 2²² = 120325905811 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120330100093 and 120330100102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12033010007 + ... + 12033010016.

It is an arithmetic number, because the mean of its divisors is an integer number (36099030036).

Almost surely, 2^120330100115 is an apocalyptic number.

120330100115 is a deficient number, since it is larger than the sum of its proper divisors (24066020029).

120330100115 is an equidigital number, since it uses as much as digits as its factorization.

120330100115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24066020028.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 120330100115 its reverse (511001033021), we get a palindrome (631331133136).

The spelling of 120330100115 in words is "one hundred twenty billion, three hundred thirty million, one hundred thousand, one hundred fifteen".