Base | Representation |
---|---|
bin | 10110011010011100… |
… | …10111110100001001 |
3 | 1011001121021022221212 |
4 | 23031032113310021 |
5 | 144120424001213 |
6 | 5310005342505 |
7 | 604122036203 |
oct | 131516276411 |
9 | 34047238855 |
10 | 12033031433 |
11 | 5115372685 |
12 | 23b9a07a35 |
13 | 1199c5b557 |
14 | 822179773 |
15 | 4a65e79a8 |
hex | 2cd397d09 |
12033031433 has 4 divisors (see below), whose sum is σ = 12127779840. Its totient is φ = 11938283028.
The previous prime is 12033031429. The next prime is 12033031441. The reversal of 12033031433 is 33413033021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12033031433 - 22 = 12033031429 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12033031399 and 12033031408.
It is not an unprimeable number, because it can be changed into a prime (12033031333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47374013 + ... + 47374266.
It is an arithmetic number, because the mean of its divisors is an integer number (3031944960).
Almost surely, 212033031433 is an apocalyptic number.
It is an amenable number.
12033031433 is a deficient number, since it is larger than the sum of its proper divisors (94748407).
12033031433 is an equidigital number, since it uses as much as digits as its factorization.
12033031433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94748406.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 12033031433 its reverse (33413033021), we get a palindrome (45446064454).
The spelling of 12033031433 in words is "twelve billion, thirty-three million, thirty-one thousand, four hundred thirty-three".
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