120331441214131 has 4 divisors (see below), whose sum is σ = 137521647101872. Its totient is φ = 103141235326392.

The previous prime is 120331441214119. The next prime is 120331441214177. The reversal of 120331441214131 is 131412144133021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120331441214131 - 2⁷ = 120331441214003 is a prime.

It is a super-2 number, since 2×120331441214131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120331441214093 and 120331441214102.

It is not an unprimeable number, because it can be changed into a prime (120331441214111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8595102943860 + ... + 8595102943873.

It is an arithmetic number, because the mean of its divisors is an integer number (34380411775468).

Almost surely, 2^{120331441214131} is an apocalyptic number.

120331441214131 is a deficient number, since it is larger than the sum of its proper divisors (17190205887741).

120331441214131 is an equidigital number, since it uses as much as digits as its factorization.

120331441214131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17190205887740.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 120331441214131 its reverse (131412144133021), we get a palindrome (251743585347152).

The spelling of 120331441214131 in words is "one hundred twenty trillion, three hundred thirty-one billion, four hundred forty-one million, two hundred fourteen thousand, one hundred thirty-one".