12033224114433 has 4 divisors (see below), whose sum is σ = 16044298819248. Its totient is φ = 8022149409620.

The previous prime is 12033224114413. The next prime is 12033224114437. The reversal of 12033224114433 is 33441142233021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12033224114433 - 2¹⁶ = 12033224048897 is a prime.

It is a super-2 number, since 2×12033224114433² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12033224114394 and 12033224114403.

It is not an unprimeable number, because it can be changed into a prime (12033224114437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2005537352403 + ... + 2005537352408.

It is an arithmetic number, because the mean of its divisors is an integer number (4011074704812).

Almost surely, 2^{12033224114433} is an apocalyptic number.

It is an amenable number.

12033224114433 is a deficient number, since it is larger than the sum of its proper divisors (4011074704815).

12033224114433 is an equidigital number, since it uses as much as digits as its factorization.

12033224114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4011074704814.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 12033224114433 its reverse (33441142233021), we get a palindrome (45474366347454).

The spelling of 12033224114433 in words is "twelve trillion, thirty-three billion, two hundred twenty-four million, one hundred fourteen thousand, four hundred thirty-three".