Search a number
-
+
120401321041 = 274274389883
BaseRepresentation
bin111000000100001111…
…0100101110001010001
3102111202222022211110201
41300020132211301101
53433040214233131
6131151150055201
711461441225411
oct1601036456121
9374688284421
10120401321041
1147075452601
121b4021aa501
13b47a39c041
145b82772641
1531ea32a761
hex1c087a5c51

120401321041 has 4 divisors (see below), whose sum is σ = 120405738352. Its totient is φ = 120396903732.

The previous prime is 120401320973. The next prime is 120401321059. The reversal of 120401321041 is 140123104021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 140123104021 = 586723883263.

It is a cyclic number.

It is not a de Polignac number, because 120401321041 - 213 = 120401312849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120401321741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167515 + ... + 2222368.

It is an arithmetic number, because the mean of its divisors is an integer number (30101434588).

Almost surely, 2120401321041 is an apocalyptic number.

It is an amenable number.

120401321041 is a deficient number, since it is larger than the sum of its proper divisors (4417311).

120401321041 is an equidigital number, since it uses as much as digits as its factorization.

120401321041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4417310.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 120401321041 its reverse (140123104021), we get a palindrome (260524425062).

The spelling of 120401321041 in words is "one hundred twenty billion, four hundred one million, three hundred twenty-one thousand, forty-one".

Divisors: 1 27427 4389883 120401321041