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12040151153 = 28142847513
BaseRepresentation
bin10110011011010011…
…00010000001110001
31011002002200001101012
423031221202001301
5144124234314103
65310422120305
7604236411332
oct131551420161
934062601335
1012040151153
115119395848
122400280095
13119b5820c4
148230b0289
154a70522d8
hex2cda62071

12040151153 has 4 divisors (see below), whose sum is σ = 12082998948. Its totient is φ = 11997303360.

The previous prime is 12040151141. The next prime is 12040151171. The reversal of 12040151153 is 35115104021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8757777889 + 3282373264 = 93583^2 + 57292^2 .

It is a cyclic number.

It is not a de Polignac number, because 12040151153 - 26 = 12040151089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12040151953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21423476 + ... + 21424037.

It is an arithmetic number, because the mean of its divisors is an integer number (3020749737).

Almost surely, 212040151153 is an apocalyptic number.

It is an amenable number.

12040151153 is a deficient number, since it is larger than the sum of its proper divisors (42847795).

12040151153 is an equidigital number, since it uses as much as digits as its factorization.

12040151153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42847794.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 12040151153 its reverse (35115104021), we get a palindrome (47155255174).

The spelling of 12040151153 in words is "twelve billion, forty million, one hundred fifty-one thousand, one hundred fifty-three".

Divisors: 1 281 42847513 12040151153