120406081888153 has 4 divisors (see below), whose sum is σ = 120557156019300. Its totient is φ = 120255007757008.

The previous prime is 120406081888091. The next prime is 120406081888159. The reversal of 120406081888153 is 351888180604021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74882075754249 + 45524006133904 = 8653443^2 + 6747148^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120406081888153 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120406081888094 and 120406081888103.

It is not an unprimeable number, because it can be changed into a prime (120406081888159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75537064378 + ... + 75537065971.

It is an arithmetic number, because the mean of its divisors is an integer number (30139289004825).

Almost surely, 2^{120406081888153} is an apocalyptic number.

It is an amenable number.

120406081888153 is a deficient number, since it is larger than the sum of its proper divisors (151074131147).

120406081888153 is an equidigital number, since it uses as much as digits as its factorization.

120406081888153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151074131146.

The product of its (nonzero) digits is 2949120, while the sum is 55.

The spelling of 120406081888153 in words is "one hundred twenty trillion, four hundred six billion, eighty-one million, eight hundred eighty-eight thousand, one hundred fifty-three".