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120410112131 = 463260065037
BaseRepresentation
bin111000000100100000…
…0001000000010000011
3102111210120212110120122
41300021000020002003
53433044442042011
6131152102330455
711461606031411
oct1601100100203
9374716773518
10120410112131
114707a407471
121b405129a2b
13b47c15957a
145b839c02b1
1531eaeb53db
hex1c09008083

120410112131 has 4 divisors (see below), whose sum is σ = 120670177632. Its totient is φ = 120150046632.

The previous prime is 120410112127. The next prime is 120410112133. The reversal of 120410112131 is 131211014021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120410112131 - 22 = 120410112127 is a prime.

It is a super-2 number, since 2×1204101121312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120410112133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130032056 + ... + 130032981.

It is an arithmetic number, because the mean of its divisors is an integer number (30167544408).

Almost surely, 2120410112131 is an apocalyptic number.

120410112131 is a deficient number, since it is larger than the sum of its proper divisors (260065501).

120410112131 is an equidigital number, since it uses as much as digits as its factorization.

120410112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260065500.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 120410112131 its reverse (131211014021), we get a palindrome (251621126152).

The spelling of 120410112131 in words is "one hundred twenty billion, four hundred ten million, one hundred twelve thousand, one hundred thirty-one".

Divisors: 1 463 260065037 120410112131