Base | Representation |
---|---|
bin | 10110011011011100… |
… | …00100110111100001 |
3 | 1011002011220120111200 |
4 | 23031232010313201 |
5 | 144130040424213 |
6 | 5310503431413 |
7 | 604252502421 |
oct | 131556046741 |
9 | 34064816450 |
10 | 12041342433 |
11 | 511a02987a |
12 | 2400755569 |
13 | 119b8ab3c3 |
14 | 823300481 |
15 | 4a71da273 |
hex | 2cdb84de1 |
12041342433 has 12 divisors (see below), whose sum is σ = 17410301220. Its totient is φ = 8019599616.
The previous prime is 12041342393. The next prime is 12041342459. The reversal of 12041342433 is 33424314021.
12041342433 is a `hidden beast` number, since 1 + 2 + 0 + 413 + 4 + 243 + 3 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 4310185104 + 7731157329 = 65652^2 + 87927^2 .
It is not a de Polignac number, because 12041342433 - 213 = 12041334241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12041342397 and 12041342406.
It is not an unprimeable number, because it can be changed into a prime (12041342333) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 653916 + ... + 672077.
It is an arithmetic number, because the mean of its divisors is an integer number (1450858435).
Almost surely, 212041342433 is an apocalyptic number.
It is an amenable number.
12041342433 is a deficient number, since it is larger than the sum of its proper divisors (5368958787).
12041342433 is a wasteful number, since it uses less digits than its factorization.
12041342433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1327008 (or 1327005 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 12041342433 its reverse (33424314021), we get a palindrome (45465656454).
The spelling of 12041342433 in words is "twelve billion, forty-one million, three hundred forty-two thousand, four hundred thirty-three".
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