120423423001331 has 4 divisors (see below), whose sum is σ = 121190451173472. Its totient is φ = 119656394829192.

The previous prime is 120423423001327. The next prime is 120423423001351. The reversal of 120423423001331 is 133100324324021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120423423001331 - 2² = 120423423001327 is a prime.

It is a super-3 number, since 3×120423423001331³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120423423001294 and 120423423001303.

It is not an unprimeable number, because it can be changed into a prime (120423423001351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 383514085835 + ... + 383514086148.

It is an arithmetic number, because the mean of its divisors is an integer number (30297612793368).

Almost surely, 2^{120423423001331} is an apocalyptic number.

120423423001331 is a deficient number, since it is larger than the sum of its proper divisors (767028172141).

120423423001331 is an equidigital number, since it uses as much as digits as its factorization.

120423423001331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 767028172140.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 120423423001331 its reverse (133100324324021), we get a palindrome (253523747325352).

The spelling of 120423423001331 in words is "one hundred twenty trillion, four hundred twenty-three billion, four hundred twenty-three million, one thousand, three hundred thirty-one".