Base | Representation |
---|---|
bin | 11011011000011001101110… |
… | …011010100110001101000011 |
3 | 120210101102202202101110112011 |
4 | 123120121232122212031003 |
5 | 111241012122222324420 |
6 | 1104042031055113351 |
7 | 34236233405431516 |
oct | 3330315632461503 |
9 | 523342682343464 |
10 | 120424145511235 |
11 | 35409658765575 |
12 | 1160b00a812857 |
13 | 5226c43251067 |
14 | 21a47b9d08d7d |
15 | ddc795bd495a |
hex | 6d866e6a6343 |
120424145511235 has 16 divisors (see below), whose sum is σ = 145865956056480. Its totient is φ = 95435040430080.
The previous prime is 120424145511203. The next prime is 120424145511269. The reversal of 120424145511235 is 532115541424021.
It is not a de Polignac number, because 120424145511235 - 25 = 120424145511203 is a prime.
It is a super-2 number, since 2×1204241455112352 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21095601 + ... + 26189170.
It is an arithmetic number, because the mean of its divisors is an integer number (9116622253530).
Almost surely, 2120424145511235 is an apocalyptic number.
120424145511235 is a deficient number, since it is larger than the sum of its proper divisors (25441810545245).
120424145511235 is a wasteful number, since it uses less digits than its factorization.
120424145511235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47289558.
The product of its (nonzero) digits is 192000, while the sum is 40.
Adding to 120424145511235 its reverse (532115541424021), we get a palindrome (652539686935256).
The spelling of 120424145511235 in words is "one hundred twenty trillion, four hundred twenty-four billion, one hundred forty-five million, five hundred eleven thousand, two hundred thirty-five".
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