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120433003113 = 3311129081461
BaseRepresentation
bin111000000101001011…
…1011100101001101001
3102111212011221110002210
41300022113130221221
53433121322044423
6131154241115333
711462304431103
oct1601227345151
9374764843083
10120433003113
1147091321835
121b410928b49
13b483b12827
145b86a5c573
1531eced7b93
hex1c0a5dca69

120433003113 has 8 divisors (see below), whose sum is σ = 161093664576. Its totient is φ = 80030505200.

The previous prime is 120433003091. The next prime is 120433003123. The reversal of 120433003113 is 311300334021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120433003113 - 25 = 120433003081 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120433003113.

It is not an unprimeable number, because it can be changed into a prime (120433003123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 64539798 + ... + 64541663.

It is an arithmetic number, because the mean of its divisors is an integer number (20136708072).

Almost surely, 2120433003113 is an apocalyptic number.

It is an amenable number.

120433003113 is a deficient number, since it is larger than the sum of its proper divisors (40660661463).

120433003113 is a wasteful number, since it uses less digits than its factorization.

120433003113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129081775.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 120433003113 its reverse (311300334021), we get a palindrome (431733337134).

The spelling of 120433003113 in words is "one hundred twenty billion, four hundred thirty-three million, three thousand, one hundred thirteen".

Divisors: 1 3 311 933 129081461 387244383 40144334371 120433003113