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12043312041 = 34014437347
BaseRepresentation
bin10110011011101011…
…00101101110101001
31011002022121122022010
423031311211232221
5144131041441131
65311013550133
7604305314625
oct131565455651
934068548263
1012043312041
115120154652
122401345349
13119c11aa57
14823694185
154a7478b46
hex2cdd65ba9

12043312041 has 4 divisors (see below), whose sum is σ = 16057749392. Its totient is φ = 8028874692.

The previous prime is 12043312037. The next prime is 12043312069. The reversal of 12043312041 is 14021334021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12043312041 - 22 = 12043312037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12043311999 and 12043312017.

It is not an unprimeable number, because it can be changed into a prime (12043312031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2007218671 + ... + 2007218676.

It is an arithmetic number, because the mean of its divisors is an integer number (4014437348).

Almost surely, 212043312041 is an apocalyptic number.

It is an amenable number.

12043312041 is a deficient number, since it is larger than the sum of its proper divisors (4014437351).

12043312041 is an equidigital number, since it uses as much as digits as its factorization.

12043312041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4014437350.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 12043312041 its reverse (14021334021), we get a palindrome (26064646062).

The spelling of 12043312041 in words is "twelve billion, forty-three million, three hundred twelve thousand, forty-one".

Divisors: 1 3 4014437347 12043312041