Base | Representation |
---|---|
bin | 10110011011110000… |
… | …10001000110110011 |
3 | 1011002100221022012201 |
4 | 23031320101012303 |
5 | 144131231422003 |
6 | 5311041004031 |
7 | 604314300310 |
oct | 131570210663 |
9 | 34070838181 |
10 | 12044014003 |
11 | 5120593a8a |
12 | 2401623617 |
13 | 119c305408 |
14 | 8237d7d07 |
15 | 4a7566b1d |
hex | 2cde111b3 |
12044014003 has 8 divisors (see below), whose sum is σ = 13798244960. Its totient is φ = 10298197440.
The previous prime is 12044013977. The next prime is 12044014039. The reversal of 12044014003 is 30041044021.
12044014003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12044014003 - 213 = 12044005811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12044014043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2100528 + ... + 2106253.
It is an arithmetic number, because the mean of its divisors is an integer number (1724780620).
Almost surely, 212044014003 is an apocalyptic number.
12044014003 is a deficient number, since it is larger than the sum of its proper divisors (1754230957).
12044014003 is an equidigital number, since it uses as much as digits as its factorization.
12044014003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4207197.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 12044014003 its reverse (30041044021), we get a palindrome (42085058024).
The spelling of 12044014003 in words is "twelve billion, forty-four million, fourteen thousand, three".
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