Base | Representation |
---|---|
bin | 10110011011110010… |
… | …10111011100110011 |
3 | 1011002101110221110010 |
4 | 23031321113130303 |
5 | 144131320132011 |
6 | 5311051110003 |
7 | 604316610321 |
oct | 131571273463 |
9 | 34071427403 |
10 | 12044302131 |
11 | 5120770504 |
12 | 2401742303 |
13 | 119c3a65c4 |
14 | 823870d11 |
15 | 4a75c21a6 |
hex | 2cde57733 |
12044302131 has 4 divisors (see below), whose sum is σ = 16059069512. Its totient is φ = 8029534752.
The previous prime is 12044302121. The next prime is 12044302139. The reversal of 12044302131 is 13120344021.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13120344021 = 3 ⋅4373448007.
It is a de Polignac number, because none of the positive numbers 2k-12044302131 is a prime.
It is a super-2 number, since 2×120443021312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12044302098 and 12044302107.
It is not an unprimeable number, because it can be changed into a prime (12044302139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2007383686 + ... + 2007383691.
It is an arithmetic number, because the mean of its divisors is an integer number (4014767378).
Almost surely, 212044302131 is an apocalyptic number.
12044302131 is a deficient number, since it is larger than the sum of its proper divisors (4014767381).
12044302131 is an equidigital number, since it uses as much as digits as its factorization.
12044302131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4014767380.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 12044302131 its reverse (13120344021), we get a palindrome (25164646152).
The spelling of 12044302131 in words is "twelve billion, forty-four million, three hundred two thousand, one hundred thirty-one".
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