120520433324241 has 6 divisors (see below), whose sum is σ = 174085070357250. Its totient is φ = 80346955549488.

The previous prime is 120520433324147. The next prime is 120520433324279. The reversal of 120520433324241 is 142423334025021.

120520433324241 is a `hidden beast` number, since 1 + 2 + 0 + 52 + 0 + 43 + 3 + 324 + 241 = 666.

It can be written as a sum of positive squares in only one way, i.e., 86193677243025 + 34326756081216 = 9284055^2 + 5858904^2 .

It is not a de Polignac number, because 120520433324241 - 2¹⁵ = 120520433291473 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120520433324196 and 120520433324205.

It is not an unprimeable number, because it can be changed into a prime (120520433324281) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6695579629116 + ... + 6695579629133.

It is an arithmetic number, because the mean of its divisors is an integer number (29014178392875).

Almost surely, 2^{120520433324241} is an apocalyptic number.

It is an amenable number.

120520433324241 is a deficient number, since it is larger than the sum of its proper divisors (53564637033009).

120520433324241 is a wasteful number, since it uses less digits than its factorization.

120520433324241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13391159258255 (or 13391159258252 counting only the distinct ones).

The product of its (nonzero) digits is 138240, while the sum is 36.

Adding to 120520433324241 its reverse (142423334025021), we get a palindrome (262943767349262).

The spelling of 120520433324241 in words is "one hundred twenty trillion, five hundred twenty billion, four hundred thirty-three million, three hundred twenty-four thousand, two hundred forty-one".