Base | Representation |
---|---|
bin | 10110011100111000… |
… | …01111011000100011 |
3 | 1011010000200101220201 |
4 | 23032130033120203 |
5 | 144141140203011 |
6 | 5312015050031 |
7 | 604460404351 |
oct | 131634173043 |
9 | 34100611821 |
10 | 12053444131 |
11 | 5125944a83 |
12 | 2404810917 |
13 | 11a1257781 |
14 | 824b707d1 |
15 | 4a82cacc1 |
hex | 2ce70f623 |
12053444131 has 16 divisors (see below), whose sum is σ = 12270712608. Its totient is φ = 11838528000.
The previous prime is 12053444119. The next prime is 12053444141. The reversal of 12053444131 is 13144435021.
It is a cyclic number.
It is not a de Polignac number, because 12053444131 - 217 = 12053313059 is a prime.
It is a super-2 number, since 2×120534441312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12053444131.
It is not an unprimeable number, because it can be changed into a prime (12053444141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7471881 + ... + 7473493.
It is an arithmetic number, because the mean of its divisors is an integer number (766919538).
Almost surely, 212053444131 is an apocalyptic number.
12053444131 is a deficient number, since it is larger than the sum of its proper divisors (217268477).
12053444131 is a wasteful number, since it uses less digits than its factorization.
12053444131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2262.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 12053444131 its reverse (13144435021), we get a palindrome (25197879152).
The spelling of 12053444131 in words is "twelve billion, fifty-three million, four hundred forty-four thousand, one hundred thirty-one".
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