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12053444131 = 1012413071613
BaseRepresentation
bin10110011100111000…
…01111011000100011
31011010000200101220201
423032130033120203
5144141140203011
65312015050031
7604460404351
oct131634173043
934100611821
1012053444131
115125944a83
122404810917
1311a1257781
14824b707d1
154a82cacc1
hex2ce70f623

12053444131 has 16 divisors (see below), whose sum is σ = 12270712608. Its totient is φ = 11838528000.

The previous prime is 12053444119. The next prime is 12053444141. The reversal of 12053444131 is 13144435021.

It is a cyclic number.

It is not a de Polignac number, because 12053444131 - 217 = 12053313059 is a prime.

It is a super-2 number, since 2×120534441312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12053444131.

It is not an unprimeable number, because it can be changed into a prime (12053444141) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7471881 + ... + 7473493.

It is an arithmetic number, because the mean of its divisors is an integer number (766919538).

Almost surely, 212053444131 is an apocalyptic number.

12053444131 is a deficient number, since it is larger than the sum of its proper divisors (217268477).

12053444131 is a wasteful number, since it uses less digits than its factorization.

12053444131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2262.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 12053444131 its reverse (13144435021), we get a palindrome (25197879152).

The spelling of 12053444131 in words is "twelve billion, fifty-three million, four hundred forty-four thousand, one hundred thirty-one".

Divisors: 1 101 241 307 1613 24341 31007 73987 162913 388733 495191 7472687 39262033 50014291 119341031 12053444131