Base | Representation |
---|---|
bin | 1010111101101000011100… |
… | …0111100111110011001011 |
3 | 1120200100100011101220100101 |
4 | 2233122013013213303023 |
5 | 3034442434424423023 |
6 | 41345301141550231 |
7 | 2352603666164131 |
oct | 257320707476313 |
9 | 46610304356311 |
10 | 12053945154763 |
11 | 392805a881036 |
12 | 1428175a15377 |
13 | 6958b38ba3c5 |
14 | 2d95b2267751 |
15 | 15d83dd051ad |
hex | af6871e7ccb |
12053945154763 has 8 divisors (see below), whose sum is σ = 12763035753408. Its totient is φ = 11344858445184.
The previous prime is 12053945154737. The next prime is 12053945154799. The reversal of 12053945154763 is 36745154935021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12053945154763 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12053945154463) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7536645 + ... + 8994937.
It is an arithmetic number, because the mean of its divisors is an integer number (1595379469176).
Almost surely, 212053945154763 is an apocalyptic number.
12053945154763 is a deficient number, since it is larger than the sum of its proper divisors (709090598645).
12053945154763 is a wasteful number, since it uses less digits than its factorization.
12053945154763 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1944533.
The product of its (nonzero) digits is 13608000, while the sum is 55.
The spelling of 12053945154763 in words is "twelve trillion, fifty-three billion, nine hundred forty-five million, one hundred fifty-four thousand, seven hundred sixty-three".
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