120551120240035 has 4 divisors (see below), whose sum is σ = 144661344288048. Its totient is φ = 96440896192024.

The previous prime is 120551120240017. The next prime is 120551120240081. The reversal of 120551120240035 is 530042021155021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120551120240035 - 2¹⁵ = 120551120207267 is a prime.

It is a super-2 number, since 2×120551120240035² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120551120239979 and 120551120240006.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12055112023999 + ... + 12055112024008.

It is an arithmetic number, because the mean of its divisors is an integer number (36165336072012).

Almost surely, 2^{120551120240035} is an apocalyptic number.

120551120240035 is a deficient number, since it is larger than the sum of its proper divisors (24110224048013).

120551120240035 is an equidigital number, since it uses as much as digits as its factorization.

120551120240035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24110224048012.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 120551120240035 its reverse (530042021155021), we get a palindrome (650593141395056).

The spelling of 120551120240035 in words is "one hundred twenty trillion, five hundred fifty-one billion, one hundred twenty million, two hundred forty thousand, thirty-five".