12080494331 has 4 divisors (see below), whose sum is σ = 12150323952. Its totient is φ = 12010664712.

The previous prime is 12080494313. The next prime is 12080494357. The reversal of 12080494331 is 13349408021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13349408021 = 56843 ⋅234847.

It is a cyclic number.

It is not a de Polignac number, because 12080494331 - 2¹⁰ = 12080493307 is a prime.

It is a super-2 number, since 2×12080494331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12080494291 and 12080494300.

It is not an unprimeable number, because it can be changed into a prime (12080424331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34914551 + ... + 34914896.

It is an arithmetic number, because the mean of its divisors is an integer number (3037580988).

Almost surely, 2^12080494331 is an apocalyptic number.

12080494331 is a deficient number, since it is larger than the sum of its proper divisors (69829621).

12080494331 is an equidigital number, since it uses as much as digits as its factorization.

12080494331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69829620.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 12080494331 in words is "twelve billion, eighty million, four hundred ninety-four thousand, three hundred thirty-one".