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1210010003513 = 198928039987
BaseRepresentation
bin10001100110111010001…
…101110110100000111001
311021200020200021222100022
4101212322031312200321
5124311100030103023
62323512041420225
7153264114220523
oct21467215664071
94250220258308
101210010003513
11427187113973
12176611a9a675
138a1463984cc
14427c9b32a13
152171d8c27c8
hex119ba376839

1210010003513 has 12 divisors (see below), whose sum is σ = 1288166877360. Its totient is φ = 1133445066336.

The previous prime is 1210010003497. The next prime is 1210010003537. The reversal of 1210010003513 is 3153000100121.

It is not a de Polignac number, because 1210010003513 - 24 = 1210010003497 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1210010003491 and 1210010003500.

It is not an unprimeable number, because it can be changed into a prime (1210010003413) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3869495 + ... + 4170492.

It is an arithmetic number, because the mean of its divisors is an integer number (107347239780).

Almost surely, 21210010003513 is an apocalyptic number.

It is an amenable number.

1210010003513 is a deficient number, since it is larger than the sum of its proper divisors (78156873847).

1210010003513 is an frugal number, since it uses more digits than its factorization.

1210010003513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8040184 (or 8040095 counting only the distinct ones).

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 1210010003513 its reverse (3153000100121), we get a palindrome (4363010103634).

The spelling of 1210010003513 in words is "one trillion, two hundred ten billion, ten million, three thousand, five hundred thirteen".

Divisors: 1 19 89 1691 7921 150499 8039987 152759753 715558843 13595618017 63684737027 1210010003513