121001211320123 has 4 divisors (see below), whose sum is σ = 121042979086680. Its totient is φ = 120959443553568.

The previous prime is 121001211320111. The next prime is 121001211320147. The reversal of 121001211320123 is 321023112100121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121001211320123 - 2³² = 120996916352827 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121001211320095 and 121001211320104.

It is not an unprimeable number, because it can be changed into a prime (121001211320623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20883878933 + ... + 20883884726.

It is an arithmetic number, because the mean of its divisors is an integer number (30260744771670).

Almost surely, 2^{121001211320123} is an apocalyptic number.

121001211320123 is a deficient number, since it is larger than the sum of its proper divisors (41767766557).

121001211320123 is an equidigital number, since it uses as much as digits as its factorization.

121001211320123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41767766556.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 121001211320123 its reverse (321023112100121), we get a palindrome (442024323420244).

The spelling of 121001211320123 in words is "one hundred twenty-one trillion, one billion, two hundred eleven million, three hundred twenty thousand, one hundred twenty-three".