12100130014003 has 4 divisors (see below), whose sum is σ = 12427160554960. Its totient is φ = 11773099473048.

The previous prime is 12100130013967. The next prime is 12100130014097. The reversal of 12100130014003 is 30041003100121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12100130014003 - 2¹⁷ = 12100129882931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12100130014403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163515270423 + ... + 163515270496.

It is an arithmetic number, because the mean of its divisors is an integer number (3106790138740).

Almost surely, 2^{12100130014003} is an apocalyptic number.

12100130014003 is a deficient number, since it is larger than the sum of its proper divisors (327030540957).

12100130014003 is an equidigital number, since it uses as much as digits as its factorization.

12100130014003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 327030540956.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12100130014003 its reverse (30041003100121), we get a palindrome (42141133114124).

The spelling of 12100130014003 in words is "twelve trillion, one hundred billion, one hundred thirty million, fourteen thousand, three".