Base | Representation |
---|---|
bin | 11011100000110011111010… |
… | …100010011101010110001011 |
3 | 120212102200100221221200222210 |
4 | 123200303322202131112023 |
5 | 111324444120113000021 |
6 | 1105203321141520203 |
7 | 34326051622514025 |
oct | 3340637242352613 |
9 | 525380327850883 |
10 | 121002022000011 |
11 | 3561173a9a2699 |
12 | 116a3004413063 |
13 | 52695985a3409 |
14 | 21c4759c5b015 |
15 | dec818677e76 |
hex | 6e0cfa89d58b |
121002022000011 has 16 divisors (see below), whose sum is σ = 163223667734400. Its totient is φ = 79725027400128.
The previous prime is 121002022000009. The next prime is 121002022000031. The reversal of 121002022000011 is 110000220200121.
It is not a de Polignac number, because 121002022000011 - 21 = 121002022000009 is a prime.
It is a super-3 number, since 3×1210020220000113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (121002022000031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103408821 + ... + 104572406.
It is an arithmetic number, because the mean of its divisors is an integer number (10201479233400).
Almost surely, 2121002022000011 is an apocalyptic number.
121002022000011 is a deficient number, since it is larger than the sum of its proper divisors (42221645734389).
121002022000011 is a wasteful number, since it uses less digits than its factorization.
121002022000011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 207983498.
The product of its (nonzero) digits is 16, while the sum is 12.
Adding to 121002022000011 its reverse (110000220200121), we get a palindrome (231002242200132).
The spelling of 121002022000011 in words is "one hundred twenty-one trillion, two billion, twenty-two million, eleven", and thus it is an aban number.
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