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12100303143003 = 34033434381001
BaseRepresentation
bin1011000000010101001001…
…0001010100000001011011
31120211202222221010201001210
42300011102101110001123
53041222410101034003
641422445202314203
72356134535450605
oct260052221240133
946752887121053
1012100303143003
113945789740809
121435153058963
1369a090c5a88a
142db92cdd0175
1515eb53a8a503
hexb015245405b

12100303143003 has 4 divisors (see below), whose sum is σ = 16133737524008. Its totient is φ = 8066868762000.

The previous prime is 12100303142971. The next prime is 12100303143037. The reversal of 12100303143003 is 30034130300121.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12100303143003 - 25 = 12100303142971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12100303143403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2016717190498 + ... + 2016717190503.

It is an arithmetic number, because the mean of its divisors is an integer number (4033434381002).

Almost surely, 212100303143003 is an apocalyptic number.

12100303143003 is a deficient number, since it is larger than the sum of its proper divisors (4033434381005).

12100303143003 is an equidigital number, since it uses as much as digits as its factorization.

12100303143003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4033434381004.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 12100303143003 its reverse (30034130300121), we get a palindrome (42134433443124).

The spelling of 12100303143003 in words is "twelve trillion, one hundred billion, three hundred three million, one hundred forty-three thousand, three".

Divisors: 1 3 4033434381001 12100303143003