121003331130001 has 4 divisors (see below), whose sum is σ = 121003767985392. Its totient is φ = 121002894274612.

The previous prime is 121003331129929. The next prime is 121003331130043. The reversal of 121003331130001 is 100031133300121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121003331130001 - 2²¹ = 121003329032849 is a prime.

It is a super-2 number, since 2×121003331130001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121003331130061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218011951 + ... + 218566276.

It is an arithmetic number, because the mean of its divisors is an integer number (30250941996348).

Almost surely, 2^{121003331130001} is an apocalyptic number.

It is an amenable number.

121003331130001 is a deficient number, since it is larger than the sum of its proper divisors (436855391).

121003331130001 is an equidigital number, since it uses as much as digits as its factorization.

121003331130001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 436855390.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 121003331130001 its reverse (100031133300121), we get a palindrome (221034464430122).

The spelling of 121003331130001 in words is "one hundred twenty-one trillion, three billion, three hundred thirty-one million, one hundred thirty thousand, one".