Base | Representation |
---|---|
bin | 1011000000010101101000… |
… | …0101011001000000101001 |
3 | 1120211210100001210220001222 |
4 | 2300011122011121000221 |
5 | 3041223142131013213 |
6 | 41422510204151425 |
7 | 2356141016641355 |
oct | 260053205310051 |
9 | 46753301726058 |
10 | 12100434235433 |
11 | 3945846739465 |
12 | 143518ab38575 |
13 | 69a0b216966b |
14 | 2db942596465 |
15 | 15eb60332808 |
hex | b015a159029 |
12100434235433 has 4 divisors (see below), whose sum is σ = 12102669680388. Its totient is φ = 12098198790480.
The previous prime is 12100434235349. The next prime is 12100434235451. The reversal of 12100434235433 is 33453243400121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4254368262544 + 7846065972889 = 2062612^2 + 2801083^2 .
It is a cyclic number.
It is not a de Polignac number, because 12100434235433 - 220 = 12100433186857 is a prime.
It is a super-2 number, since 2×121004342354332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12100434235393 and 12100434235402.
It is not an unprimeable number, because it can be changed into a prime (12100434235133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1117714358 + ... + 1117725183.
It is an arithmetic number, because the mean of its divisors is an integer number (3025667420097).
Almost surely, 212100434235433 is an apocalyptic number.
It is an amenable number.
12100434235433 is a deficient number, since it is larger than the sum of its proper divisors (2235444955).
12100434235433 is an equidigital number, since it uses as much as digits as its factorization.
12100434235433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2235444954.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 12100434235433 its reverse (33453243400121), we get a palindrome (45553677635554).
The spelling of 12100434235433 in words is "twelve trillion, one hundred billion, four hundred thirty-four million, two hundred thirty-five thousand, four hundred thirty-three".
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