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12100434553 = 64177324421
BaseRepresentation
bin10110100010011110…
…11111101001111001
31011020022002202122201
423101033133221321
5144240202401203
65320414150201
7605600665564
oct132117375171
934208082581
1012100434553
11514a41a639
1224184b2361
1311aabcb05c
1482b0c34db
154ac4ade1d
hex2d13dfa79

12100434553 has 8 divisors (see below), whose sum is σ = 12135487176. Its totient is φ = 12065433600.

The previous prime is 12100434551. The next prime is 12100434557. The reversal of 12100434553 is 35543400121.

It can be written as a sum of positive squares in 4 ways, for example, as 8573184 + 12091861369 = 2928^2 + 109963^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12100434553 - 21 = 12100434551 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12100434551) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 483283 + ... + 507703.

It is an arithmetic number, because the mean of its divisors is an integer number (1516935897).

Almost surely, 212100434553 is an apocalyptic number.

It is an amenable number.

12100434553 is a deficient number, since it is larger than the sum of its proper divisors (35052623).

12100434553 is an equidigital number, since it uses as much as digits as its factorization.

12100434553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25835.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 12100434553 its reverse (35543400121), we get a palindrome (47643834674).

The spelling of 12100434553 in words is "twelve billion, one hundred million, four hundred thirty-four thousand, five hundred fifty-three".

Divisors: 1 641 773 24421 495493 15653861 18877433 12100434553