1210046790947 has 4 divisors (see below), whose sum is σ = 1210049230776. Its totient is φ = 1210044351120.

The previous prime is 1210046790913. The next prime is 1210046791007. The reversal of 1210046790947 is 7490976400121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1210046790947 - 2⁸ = 1210046790691 is a prime.

It is a super-2 number, since 2×1210046790947² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1210046790895 and 1210046790904.

It is not an unprimeable number, because it can be changed into a prime (1210046790047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181133 + ... + 1566174.

It is an arithmetic number, because the mean of its divisors is an integer number (302512307694).

Almost surely, 2^{1210046790947} is an apocalyptic number.

1210046790947 is a deficient number, since it is larger than the sum of its proper divisors (2439829).

1210046790947 is an equidigital number, since it uses as much as digits as its factorization.

1210046790947 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2439828.

The product of its (nonzero) digits is 762048, while the sum is 50.

The spelling of 1210046790947 in words is "one trillion, two hundred ten billion, forty-six million, seven hundred ninety thousand, nine hundred forty-seven".