121012101100113 has 4 divisors (see below), whose sum is σ = 161349468133488. Its totient is φ = 80674734066740.

The previous prime is 121012101100081. The next prime is 121012101100193. The reversal of 121012101100113 is 311001101210121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121012101100113 - 2⁵ = 121012101100081 is a prime.

It is a super-2 number, since 2×121012101100113² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121012101100092 and 121012101100101.

It is not an unprimeable number, because it can be changed into a prime (121012101100193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20168683516683 + ... + 20168683516688.

It is an arithmetic number, because the mean of its divisors is an integer number (40337367033372).

Almost surely, 2^{121012101100113} is an apocalyptic number.

It is an amenable number.

121012101100113 is a deficient number, since it is larger than the sum of its proper divisors (40337367033375).

121012101100113 is an equidigital number, since it uses as much as digits as its factorization.

121012101100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40337367033374.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 121012101100113 its reverse (311001101210121), we get a palindrome (432013202310234).

The spelling of 121012101100113 in words is "one hundred twenty-one trillion, twelve billion, one hundred one million, one hundred thousand, one hundred thirteen".