Base | Representation |
---|---|
bin | 1011000000011001011000… |
… | …1110011111011100010001 |
3 | 1120211212221101110100101020 |
4 | 2300012112032133130101 |
5 | 3041232223433112113 |
6 | 41423154251030053 |
7 | 2356205021313510 |
oct | 260062616373421 |
9 | 46755841410336 |
10 | 12101443254033 |
11 | 3946214262031 |
12 | 1435410a3b329 |
13 | 69a2132137a3 |
14 | 2db9da5b0677 |
15 | 15ebbdbe6023 |
hex | b019639f711 |
12101443254033 has 8 divisors (see below), whose sum is σ = 18440294482368. Its totient is φ = 6915110430864.
The previous prime is 12101443253899. The next prime is 12101443254149. The reversal of 12101443254033 is 33045234410121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12101443254033 - 28 = 12101443253777 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12101443253985 and 12101443254003.
It is not an unprimeable number, because it can be changed into a prime (12101403254033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 288129601266 + ... + 288129601307.
It is an arithmetic number, because the mean of its divisors is an integer number (2305036810296).
Almost surely, 212101443254033 is an apocalyptic number.
It is an amenable number.
12101443254033 is a deficient number, since it is larger than the sum of its proper divisors (6338851228335).
12101443254033 is an equidigital number, since it uses as much as digits as its factorization.
12101443254033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 576259202583.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 12101443254033 its reverse (33045234410121), we get a palindrome (45146677664154).
The spelling of 12101443254033 in words is "twelve trillion, one hundred one billion, four hundred forty-three million, two hundred fifty-four thousand, thirty-three".
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