Base | Representation |
---|---|
bin | 10110100010101011… |
… | …00000100011101011 |
3 | 1011020102001212021220 |
4 | 23101111200203223 |
5 | 144241103323430 |
6 | 5320512033123 |
7 | 605620253145 |
oct | 132125404353 |
9 | 34212055256 |
10 | 12102011115 |
11 | 51502a7087 |
12 | 2418b327a3 |
13 | 11ab33082c |
14 | 82b3b3c95 |
15 | 4ac6c1110 |
hex | 2d15608eb |
12102011115 has 16 divisors (see below), whose sum is σ = 19364587008. Its totient is φ = 6453949536.
The previous prime is 12102011101. The next prime is 12102011137. The reversal of 12102011115 is 51111020121.
It is not a de Polignac number, because 12102011115 - 219 = 12101486827 is a prime.
It is a super-3 number, since 3×121020111153 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a junction number, because it is equal to n+sod(n) for n = 12102011094 and 12102011103.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 372972 + ... + 404118.
It is an arithmetic number, because the mean of its divisors is an integer number (1210286688).
Almost surely, 212102011115 is an apocalyptic number.
12102011115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12102011115 is a deficient number, since it is larger than the sum of its proper divisors (7262575893).
12102011115 is a wasteful number, since it uses less digits than its factorization.
12102011115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57058.
The product of its (nonzero) digits is 20, while the sum is 15.
Adding to 12102011115 its reverse (51111020121), we get a palindrome (63213031236).
The spelling of 12102011115 in words is "twelve billion, one hundred two million, eleven thousand, one hundred fifteen".
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