12102033303001 has 4 divisors (see below), whose sum is σ = 12106938872272. Its totient is φ = 12097127733732.

The previous prime is 12102033302993. The next prime is 12102033303043. The reversal of 12102033303001 is 10030333020121.

12102033303001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12102033303001 - 2³ = 12102033302993 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12102033303001.

It is not an unprimeable number, because it can be changed into a prime (12102033300001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2452780935 + ... + 2452785868.

It is an arithmetic number, because the mean of its divisors is an integer number (3026734718068).

Almost surely, 2^{12102033303001} is an apocalyptic number.

It is an amenable number.

12102033303001 is a deficient number, since it is larger than the sum of its proper divisors (4905569271).

12102033303001 is an equidigital number, since it uses as much as digits as its factorization.

12102033303001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4905569270.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 12102033303001 its reverse (10030333020121), we get a palindrome (22132366323122).

The spelling of 12102033303001 in words is "twelve trillion, one hundred two billion, thirty-three million, three hundred three thousand, one".