1210214113 has 4 divisors (see below), whose sum is σ = 1218228928. Its totient is φ = 1202199300.

The previous prime is 1210214107. The next prime is 1210214123. The reversal of 1210214113 is 3114120121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1210214113 - 2⁵ = 1210214081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1210214123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4007181 + ... + 4007482.

It is an arithmetic number, because the mean of its divisors is an integer number (304557232).

Almost surely, 2^1210214113 is an apocalyptic number.

It is an amenable number.

1210214113 is a deficient number, since it is larger than the sum of its proper divisors (8014815).

1210214113 is an equidigital number, since it uses as much as digits as its factorization.

1210214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8014814.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1210214113 is about 34788.1317836989. The cubic root of 1210214113 is about 1065.6650868590.

Adding to 1210214113 its reverse (3114120121), we get a palindrome (4324334234).

The spelling of 1210214113 in words is "one billion, two hundred ten million, two hundred fourteen thousand, one hundred thirteen".