Base | Representation |
---|---|
bin | 10110100010101110… |
… | …00111110101010011 |
3 | 1011020102212100120011 |
4 | 23101113013311103 |
5 | 144241210343011 |
6 | 5320525055351 |
7 | 605623664344 |
oct | 132127076523 |
9 | 34212770504 |
10 | 12102434131 |
11 | 5150565987 |
12 | 24190b7557 |
13 | 11ab44b238 |
14 | 82b4840cb |
15 | 4ac756621 |
hex | 2d15c7d53 |
12102434131 has 8 divisors (see below), whose sum is σ = 12603394944. Its totient is φ = 11608383360.
The previous prime is 12102434087. The next prime is 12102434159. The reversal of 12102434131 is 13143420121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12102434131 - 219 = 12101909843 is a prime.
It is a super-2 number, since 2×121024341312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12102434231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1723936 + ... + 1730941.
It is an arithmetic number, because the mean of its divisors is an integer number (1575424368).
Almost surely, 212102434131 is an apocalyptic number.
12102434131 is a deficient number, since it is larger than the sum of its proper divisors (500960813).
12102434131 is a wasteful number, since it uses less digits than its factorization.
12102434131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3455021.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 12102434131 its reverse (13143420121), we get a palindrome (25245854252).
The spelling of 12102434131 in words is "twelve billion, one hundred two million, four hundred thirty-four thousand, one hundred thirty-one".
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