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1210244214113 = 11225148877033
BaseRepresentation
bin10001100111001000001…
…011010010110101100001
311021200212000000002212222
4101213020023102311201
5124312040004322423
62323551205400425
7153302660041334
oct21471013226541
94250760002788
101210244214113
11427297342850
12176678409115
138a182a7016c
144280cc9c61b
15217342383c8
hex119c82d2d61

1210244214113 has 8 divisors (see below), whose sum is σ = 1320852966816. Its totient is φ = 1099733220000.

The previous prime is 1210244214089. The next prime is 1210244214121. The reversal of 1210244214113 is 3114124420121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1210244214113 - 210 = 1210244213089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1210244214173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24413756 + ... + 24463277.

It is an arithmetic number, because the mean of its divisors is an integer number (165106620852).

Almost surely, 21210244214113 is an apocalyptic number.

It is an amenable number.

1210244214113 is a deficient number, since it is larger than the sum of its proper divisors (110608752703).

1210244214113 is a wasteful number, since it uses less digits than its factorization.

1210244214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48879295.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 1210244214113 its reverse (3114124420121), we get a palindrome (4324368634234).

The spelling of 1210244214113 in words is "one trillion, two hundred ten billion, two hundred forty-four million, two hundred fourteen thousand, one hundred thirteen".

Divisors: 1 11 2251 24761 48877033 537647363 110022201283 1210244214113