Base | Representation |
---|---|
bin | 111000010110111110… |
… | …0110100000111011001 |
3 | 102120101210022002101211 |
4 | 1300231330310013121 |
5 | 3440332140013423 |
6 | 131333404543121 |
7 | 11513144015050 |
oct | 1605574640731 |
9 | 376353262354 |
10 | 121030001113 |
11 | 4736830a20a |
12 | 1b558851aa1 |
13 | b54a6c9b98 |
14 | 5c02063397 |
15 | 323561110d |
hex | 1c2df341d9 |
121030001113 has 16 divisors (see below), whose sum is σ = 140897304576. Its totient is φ = 101820131280.
The previous prime is 121030001101. The next prime is 121030001123. The reversal of 121030001113 is 311100030121.
It is not a de Polignac number, because 121030001113 - 213 = 121029992921 is a prime.
It is a super-2 number, since 2×1210300011132 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121030001093 and 121030001102.
It is not an unprimeable number, because it can be changed into a prime (121030001123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 435181 + ... + 656842.
It is an arithmetic number, because the mean of its divisors is an integer number (8806081536).
Almost surely, 2121030001113 is an apocalyptic number.
It is an amenable number.
121030001113 is a deficient number, since it is larger than the sum of its proper divisors (19867303463).
121030001113 is a wasteful number, since it uses less digits than its factorization.
121030001113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1092324.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 121030001113 its reverse (311100030121), we get a palindrome (432130031234).
The spelling of 121030001113 in words is "one hundred twenty-one billion, thirty million, one thousand, one hundred thirteen".
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