Base | Representation |
---|---|
bin | 10110100010110011… |
… | …01111010010000011 |
3 | 1011020111011012101211 |
4 | 23101121233102003 |
5 | 144241344320003 |
6 | 5320551510551 |
7 | 605632552102 |
oct | 132131572203 |
9 | 34214135354 |
10 | 12103120003 |
11 | 5150994217 |
12 | 2419388457 |
13 | 11ab62b490 |
14 | 82b5c2039 |
15 | 4ac83e96d |
hex | 2d166f483 |
12103120003 has 4 divisors (see below), whose sum is σ = 13034129248. Its totient is φ = 11172110760.
The previous prime is 12103119989. The next prime is 12103120019. The reversal of 12103120003 is 30002130121.
12103120003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12103120003 - 233 = 3513185411 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 931009231 = 12103120003 / (1 + 2 + 1 + 0 + 3 + 1 + 2 + 0 + 0 + 0 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12103120033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465504603 + ... + 465504628.
It is an arithmetic number, because the mean of its divisors is an integer number (3258532312).
Almost surely, 212103120003 is an apocalyptic number.
12103120003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12103120003 is a deficient number, since it is larger than the sum of its proper divisors (931009245).
12103120003 is an equidigital number, since it uses as much as digits as its factorization.
12103120003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 931009244.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 12103120003 its reverse (30002130121), we get a palindrome (42105250124).
It can be divided in two parts, 1210 and 3120003, that added together give a palindrome (3121213).
The spelling of 12103120003 in words is "twelve billion, one hundred three million, one hundred twenty thousand, three".
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