Base | Representation |
---|---|
bin | 10110100010110101… |
… | …00001000111010001 |
3 | 1011020111112120101110 |
4 | 23101122201013101 |
5 | 144241422332423 |
6 | 5321000123533 |
7 | 605634362136 |
oct | 132132410721 |
9 | 34214476343 |
10 | 12103324113 |
11 | 5151013601 |
12 | 24194665a9 |
13 | 11ab6a035a |
14 | 82b63658d |
15 | 4ac880193 |
hex | 2d16a11d1 |
12103324113 has 4 divisors (see below), whose sum is σ = 16137765488. Its totient is φ = 8068882740.
The previous prime is 12103324073. The next prime is 12103324169. The reversal of 12103324113 is 31142330121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12103324113 - 26 = 12103324049 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12103324113.
It is not an unprimeable number, because it can be changed into a prime (12103324183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2017220683 + ... + 2017220688.
It is an arithmetic number, because the mean of its divisors is an integer number (4034441372).
Almost surely, 212103324113 is an apocalyptic number.
It is an amenable number.
12103324113 is a deficient number, since it is larger than the sum of its proper divisors (4034441375).
12103324113 is an equidigital number, since it uses as much as digits as its factorization.
12103324113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4034441374.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 12103324113 its reverse (31142330121), we get a palindrome (43245654234).
The spelling of 12103324113 in words is "twelve billion, one hundred three million, three hundred twenty-four thousand, one hundred thirteen".
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