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1210340113 = 8314582411
BaseRepresentation
bin100100000100100…
…0101001100010001
310010100110122111121
41020021011030101
54434321340423
6320033442241
741664502243
oct11011051421
93110418447
101210340113
11571229494
12299410381
131639a4aa8
14b6a62093
15713ce45d
hex48245311

1210340113 has 4 divisors (see below), whose sum is σ = 1224922608. Its totient is φ = 1195757620.

The previous prime is 1210340111. The next prime is 1210340123. The reversal of 1210340113 is 3110430121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1210340113 - 21 = 1210340111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1210340111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7291123 + ... + 7291288.

It is an arithmetic number, because the mean of its divisors is an integer number (306230652).

Almost surely, 21210340113 is an apocalyptic number.

It is an amenable number.

1210340113 is a deficient number, since it is larger than the sum of its proper divisors (14582495).

1210340113 is an equidigital number, since it uses as much as digits as its factorization.

1210340113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14582494.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1210340113 is about 34789.9426990043. The cubic root of 1210340113 is about 1065.7020690590.

Adding to 1210340113 its reverse (3110430121), we get a palindrome (4320770234).

The spelling of 1210340113 in words is "one billion, two hundred ten million, three hundred forty thousand, one hundred thirteen".

Divisors: 1 83 14582411 1210340113